Xilinx is the world's one of largest supplier of programmable logic devices. It has started R & D department in Hyderabad, India. It has broad scope for embedded system programming in device driver in linux.
Before the interview you have to feel the Xilinx form with information containing all academic details, current/previous employer, contacts of employer( to check out info about you), current ctc, expected ctc and expected date of joining, etc.
I appeared two back to back technical interviews.
The first interview was taken by a young man look like just crossed 30's.
He asked me to tell me about myself.
Then he asked my experience.
He checked my expertise in resume.
He asked questions about RTOS, and Linux Device Drivers. What is RTOS ? Define it. How a linux device driver works? How a character driver works?
He looked at my project summaries and started to ask in depth questions about each project.
After that he asked me to write to delete nth node from starting in Singly Linked Li…
The history of the Board of Secondary Education Rajasthan (BSER) is a remarkable panorama of progressive record of the futurological vision for developing a dynamic system of various sub-systems of examinations and highlights of the academic excellence of the last four decades. The BSER took rapid strides for promotion and development of Secondary Education in Rajasthan, spread over 3,42,239 sq. km. and in more than 6000 schools located in 32 districts involving 8.5 lakhs students for Secondary and Senior Secondary Examination in the year 2000.
How to delete the last character in a string? Lets say I have a string "/data/share/" I want to delete the last character from the string ie "/" so that output will be "/data/share"; Here are some methods to do this in C language. one way could be use of strncat() function; char*strncat(char*restricts1, constchar*restricts2, size_tn); The strncat() function appends not more than n characters from s2, and then adds a terminating `\0'. #include Another simple way is, say the string variable is str_p Then simply put str_p[(strlen(str_p)-1)] = '\0'; And you are done;